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Class-IX Unit-12 Heron Formula

Introduction
Area is the amount of space inside a boundary of a 2D object. Unit of area is m2, cm2, hectare, acre etc.
Area of a figure is a number in some unit, associated with the part enclosed by the figure.
We know how to find area of Right Triangle, Equilateral Triangle & Isosceles Triangle.

Heron of Egypt gave a formula to find area of ANY triangle. This formula is called Heron’s Formula or Hero’s formula. It is stated as


Where a, b and c are the sides of the triangle, and s = semi-perimeter i.e. half the perimeter of the triangle = (a + b + c)/2.,
Application of Heron’s Formula: Area of a quadrilateral whose sides and one diagonal are given, can be calculated by dividing the quadrilateral into two triangles and using the Heron’s formula.

Mensuration

  • It is branch of mathematics which is concerned about the measurement of length ,area and Volume of plane and Solid figure

Perimeter

  • The perimeter of plane figure is defined as the length of the boundary
  • It units is same as that of length i.e. m ,cm,km
1 Meter10 Decimeter100 centimeter
1 Decimeter10 centimeter100 millimeter
1 Km10 Hectometer100 Decameter
1 Decameter10 meter1000 centimeter

Area

  • The area of the plane figure is the surface enclosed by its boundary
  • It unit is square of length unit. i.e. m2 ,  km2
1 square Meter100 square Decimeter10000 square centimeter
1 square Decimeter100 square centimeter10000 square millimeter
1 Hectare100 squareDecameter10000 square meter
1 square myraimeter100 square kilometer108  square meter

Perimeter and Area of Different Figure

NShapePerimeter/heightArea
1Right angle triangle
Base =b, Height =h
Hypotenuse=d
P=b+h+d
Height =h
A=(1/2)BH
2Isosceles right angled triangle
Equal side =a
Height=aA=(1/2)a1/2
3Any triangle of sides a,b ,cP=a+b+cA=[s(s-a)(s-b)(s-c)]1/2
s=(a+b+c)/2
This is called   Heron's formula (sometimes called Hero's formula) is named after Hero of Alexandria
4Square
Side =a
  1.  
A=a2
5Rectangle of Length and breath L and B respectivelyP=2L +2BA=LX B
6Parallelograms
Two sides are given as a and b
P=2a+2bA= BaseX height
When the diagonal is also given ,say d
Then
A=[s(s-a)(s-b)(s-d)]1/2
s=(a+b+d)/2
7Rhombus
Diagonal d1 and d2 are given
p=2(d12+d22)1/2
Each side=(1/2)(d12+d22)1/2 
A=(1/2)d1d2
8Quadrilateral
a) All the sides are given a,b,c ,d
b) Both the diagonal are perpendicular to each other
c) When a diagonal and perpendicular to diagonal are given
a) P=a+b+c+da)
A=[s(s-a)(s-b)(s-c)(s-d)]1/2
s=(a+b+c+d)/2
b)A=(1/2)d1d2
where d1 and d are the diagonal
c)A=(1/2)d(h1+h2)
where d is diagonal and h1 and h2 are perpendicular to that

How to solve the Area and Perimeter problems

1) We must remember the formula for all the common figures as given above the table
2) Find out what all is given in the problem
3) Convert all the given quantites in the same unit
4) Sometimes Perimeter is given and some side  is unknown,So you can calculate the sides using the Perimeter
5) If it is a complex figure ,break down into common know figures like square,rectangle,triangle
6) Sometimes we can find another side using pythogorus theorem in the complex  figure
7) If common figure, apply the formula given above and calculate the area.
8) If complex figure, calculate the area for each common figure in it  and sum all the area at the end to calculate the total area of the figure

Solved Examples

1) A right angle traingle has base 20 cm and height as 10 cm, What is the area of the traingle?
Solution
Given values B=20 cm
H=10 cm
Both are in same units
A=(1/2)BH=100 cm2  
2) Sides of traingles  are in the ratio  12:17:25.  The perimeter of the traingle is 540 cm. Find out the area of the traingle?
Solution
Let the common ration between the sides be y,then sides are 12y,17y,25 y
Now we know the perimeter of the triangle is given by
P=a+b+c
540=12y+17y+25y
or y=10 cm
Now Area of triangle is   =[s(s-a)(s-b)(s-c)]1/2
Where s=(a+b+c)/2
Here s=270 cm
a=120 cm
b=170cm
c=250cm
Substituting all these values in the area equation,we get
A=9000cm2
3) A equilateral triangle is having side 2 cm. What is the area of the triangle?
Solution:
We know that Are of equilateral triangle is given by
A=[(3)1/2 a2]/4
Substituting the values given above
A=(3)1/2 

We can summarize various method to calculate the Area of the Triangle

If you know the altitude  and BaseArea =(1/2)BH
If you all the three sidesA=[s(s-a)(s-b)(s-c)]1/2
s=(a+b+c)/2
If it is isoceles traingle with equal side aA=(1/2)a1/2
If it is equilateral triangel  with equal side aA=[(3)1/2 a2]/4
If it is right angle triangle with Base B and Height HArea =(1/2)BH

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